| ⇦ |
| ⇨ |
If h is Planck’s constant, the momentum of a photon of wavelength 0.01 Å is
Options
(a) 10⁻² h
(b) h
(c) 10² h
(d) 10¹² h
Correct Answer:
10¹² h
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- If force is proportional to square of velocity, then the dimension of proportionality
- Tangent galvanometer is used to measure
- Equal currents are passing through two very long and straight parallel wires
- If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- If force is proportional to square of velocity, then the dimension of proportionality
- Tangent galvanometer is used to measure
- Equal currents are passing through two very long and straight parallel wires
- If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

momentum is given by p=h/lambda
As h is constant so p is inversely proportional to lambda. The value of lambda is 0.01 angstrom I.e, 1×102 Angstrom. and angstrom is equals to 10 raised to the power 10. so the equation becomes p=1/1×102×1010. p=1/1×1012
p=10 raised to the power -12. So the answer is ×10-12.