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If energy(E), velocity(V) and time(T) are chosen as fundamental quantities, the dimensional formula of surface tension will be
Options
(a) EV⁻¹T⁻²
(b) EV⁻²T⁻²
(c) E⁻²V⁻¹T⁻³
(d) EV⁻²T⁻¹
Correct Answer:
EV⁻²T⁻²
Explanation:
Let surface tension s = EᵃVᵇTᶜ
MLT⁻² / L = (ML²T⁻²)ᵃ (L / T)ᵇ (T)ᶜ
Equating the dimension of LHS and RHS
ML⁰T⁻² = MᵃL²ᵃ⁺ᵇT⁻²ᵃ⁻ᵇ⁺ᶜ
⇒ a = 1, 2a + b = 0, -2a -b + c = -2
⇒ a = 1, b = -2, c = -2
Hence, the dimensions of surface tension are [EV⁻²T⁻²].
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Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two charges of equal magnitude q are placed in air at a distance 2a
- The wavelength of the first line of Lymasn series for hydrogen atom is equal
- A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
- An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
- Two nuclei are said to be mirror nuclei of
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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