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If energy(E), velocity(V) and time(T) are chosen as fundamental quantities, the dimensional formula of surface tension will be
Options
(a) EV⁻¹T⁻²
(b) EV⁻²T⁻²
(c) E⁻²V⁻¹T⁻³
(d) EV⁻²T⁻¹
Correct Answer:
EV⁻²T⁻²
Explanation:
Let surface tension s = EᵃVᵇTᶜ
MLT⁻² / L = (ML²T⁻²)ᵃ (L / T)ᵇ (T)ᶜ
Equating the dimension of LHS and RHS
ML⁰T⁻² = MᵃL²ᵃ⁺ᵇT⁻²ᵃ⁻ᵇ⁺ᶜ
⇒ a = 1, 2a + b = 0, -2a -b + c = -2
⇒ a = 1, b = -2, c = -2
Hence, the dimensions of surface tension are [EV⁻²T⁻²].
Related Questions: - A parallel beam of light of wavelength λ is incident normally on a narrow slit
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Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A parallel beam of light of wavelength λ is incident normally on a narrow slit
- A body of mass 2 kg is moved by a force F=3x where x is the distance covered.
- Four indentical thin rods each of mass M and length l, form a square frame
- Two identical circular coils A and B are kept on a horizontal tube
- Two charged particles have charges and masses in the ratio 2:3 and 1:4 respectively.
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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