If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A

⇦

⇨

If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A in 2×10⁻³ s, then the coefficient of self-induction is

Options

(a) 2×10⁻³ H
(b) 10⁻³ H
(c) 0.5×10⁻³ H
(d) 4×10⁻³H

Correct Answer:

2×10⁻³ H

Explanation:

Induced emf, e = 2 V

i₁ = 8 A, i₂ = 6 A

∆t = 2 × 10⁻³ s

Coefficient of self-induction, L = e / (∆i/∆t)

= -2 / [(6-2) / 2 × 10⁻³]

= (-2 × 2 × 10⁻³) / -2

= 2 × 10⁻³ H

Related Questions:

1. A boy whirls a stone in a horizontal circle of radius 1.5 m and at height 2.0 m
2. A radiactive substance emits 100 beta particles in the first 2s and 50 beta
3. The energy band gap is maximum in
4. Which of the following parameters does not characterize the thermodynamic state
5. If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,

Topics: Electromagnetic Induction (76)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends