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If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A in 2×10⁻³ s, then the coefficient of self-induction is
Options
(a) 2×10⁻³ H
(b) 10⁻³ H
(c) 0.5×10⁻³ H
(d) 4×10⁻³H
Correct Answer:
2×10⁻³ H
Explanation:
Induced emf, e = 2 V
i₁ = 8 A, i₂ = 6 A
∆t = 2 × 10⁻³ s
Coefficient of self-induction, L = e / (∆i/∆t)
= -2 / [(6-2) / 2 × 10⁻³]
= (-2 × 2 × 10⁻³) / -2
= 2 × 10⁻³ H
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If F⃗ is the force acting on a particle having position vector r⃗ and ? ⃗ be the torque
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
- The logic behind NOR gate is that it gives
- A light of wavelength 5000Å falls on a sensitive plate with photoelectric work
- A coil has resistance 30 ohm and inductive reactance 20 ohmn at 50 Hz frequency.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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