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If a body is rolling on the surface, its total energy will be
Options
(a)(1/2) mv² – (Gm₁m₂/R)
(b) (1/2) mv² + (1/2) Iω²
(c) (1/2) mv² – (1/2) mR²ω²
(d) None
Correct Answer:
(1/2) mv² + (1/2) Iω²
Explanation:
Total energy = P.E. + K.E. of (linear motion + Rotation)
= 0 + (1/2) mv² + (1/2) Iω²
Total energy = (1/2) mv² + (1/2) Iω².
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
- A body of mass 4 kg is accelerated upon by a constant force travels
- An astronomical telescope arranged for normal adjustment has a magnification of 6.
- Thin uniform rod of length L, cross-sectional area A and density ρ is rotated
- The intensity at the maximum in a Young’s double slit experiment is I₀.
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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