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If a body is rolling on the surface, its total energy will be
Options
(a)(1/2) mv² – (Gm₁m₂/R)
(b) (1/2) mv² + (1/2) Iω²
(c) (1/2) mv² – (1/2) mR²ω²
(d) None
Correct Answer:
(1/2) mv² + (1/2) Iω²
Explanation:
Total energy = P.E. + K.E. of (linear motion + Rotation)
= 0 + (1/2) mv² + (1/2) Iω²
Total energy = (1/2) mv² + (1/2) Iω².
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An air core solenoid has 1000 turns and is one meter long. Its cross sectional area
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- A particle of mass M is suited at the centre of a spherical shell of same mass and radius
- The acceleration due to gravity near the surface of a planet of radius R and density d
- A step-up transformer operates on a 230 V line and supplies a current of 2 A.
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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