| ⇦ |
| ⇨ |
If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
Options
(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032
Correct Answer:
0.0164
Explanation:
Here μᵥ=1.5230and μʀ=1.5145
Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187
Now, dispersive power, ω is given by,
ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164
Related Questions: - A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
- The magnifying power of a telescope is 9. When it is adjusted for parallel rays
- According to Bohr model of hydrogen atom, only those orbits are permissible
- The unit of electric permittivity is
- A p-n photodiode is fabricated from a semiconductor with a band gap of 2.5 eV.
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
- The magnifying power of a telescope is 9. When it is adjusted for parallel rays
- According to Bohr model of hydrogen atom, only those orbits are permissible
- The unit of electric permittivity is
- A p-n photodiode is fabricated from a semiconductor with a band gap of 2.5 eV.
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply