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How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide
Options
(a) 1
(b) 2
(c) 3
(d) 4
Correct Answer:
3
Explanation:
Iodine is liberated from potassium iodide.
K₂Cr₂O₇ + 4H₂SO₄ → K₂ SO₄+ Cr₂(SO₄)₃ + 4H₂O+ 3[O]
[2KI + H₂SO₄+[O] → K₂ SO₄ + I₂ +H₂O] ⨯ 3 /
[ K₂Cr₂O₇ + 6KI + 7H₂ SO₄ → 4K₂ SO₄+ Cr₂(SO₄)₃ + 7H₂O + 3I₂].
Related Questions: - How many grams of dibasic acid (mol.wt.200) should be present in 100 mL.
- Which among the following is an extensive property of the system
- Silver sulphide dissolves in a solution of sodium cyanide to form the complex
- A bivalent metal has the equivalent weight of 12. The molecular weight
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Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- How many grams of dibasic acid (mol.wt.200) should be present in 100 mL.
- Which among the following is an extensive property of the system
- Silver sulphide dissolves in a solution of sodium cyanide to form the complex
- A bivalent metal has the equivalent weight of 12. The molecular weight
- Which of the following organic compounds polymerizes to form the polyester Dacron
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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