| ⇦ | 
| ⇨ |
How many coulombs are required for the oxidation of 1 mole H₂O to O₂
Options
(a) 3.86 x 10⁵ C
(b) 1.93 x 10⁵ C
(c) 4.825 x 10⁴ C
(d) 9.65 x 10⁴ C
Correct Answer:
1.93 x 10⁵ C
Explanation:
H₂O → H₂ + 1/2 O₂ mole. No. of electrons involved = 2 mole = 2 × 6.023 × 10²³. 1 mole of electronic charge = 96500 C. ⇒ 2 mole of electronic charge = 2 × 96500. = 1.93 × 10⁵ C.
Related Questions: - Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85g
- The coordination number of a metal in coordination compounds is
- The best method for the separation of naphthalene and benzoic acid from their
- A primary alcohol,C₃H₈O (A) on heating with sulphuric acid undergo dehydration
- If 1 mL of water contains 20 drops then number of molecules in a drop of water
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85g
- The coordination number of a metal in coordination compounds is
- The best method for the separation of naphthalene and benzoic acid from their
- A primary alcohol,C₃H₈O (A) on heating with sulphuric acid undergo dehydration
- If 1 mL of water contains 20 drops then number of molecules in a drop of water
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply