| ⇦ |
| ⇨ |
The ratio of the difference in energy between first and second Bohr orbit to that between the second and the third Bohr orbit is
Options
(a) 1/2
(b) 1/3
(c) 4/9
(d) 27/5
Correct Answer:
27/5
Explanation:
E₁ – E₂ = 1312 x Z²(1/1² – 1/2²)
= 1312 x Z²(3/4)
E₂ – E₃ = 1312 x Z²(1/2² – 1/3²)
= 1312 x Z²(5/36)
From eqs. (i) and (ii)
E₁ – E₂ / E₂ – E₃ = 3 x 26 / 4 x 5 = 27/5
Related Questions: - The concentration of [H⁺] and [OH⁻] of a 0.1 M aqueous solution of 2% ionised
- Which of the following is redox reaction
- The compound used in enrichment for uranium for nuclear power plant is
- An aqueous solution of glucose is 10% in strength. The volume in which 1g mole
- Considering the state of hybridization of carbon atoms, find out the molecule
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The concentration of [H⁺] and [OH⁻] of a 0.1 M aqueous solution of 2% ionised
- Which of the following is redox reaction
- The compound used in enrichment for uranium for nuclear power plant is
- An aqueous solution of glucose is 10% in strength. The volume in which 1g mole
- Considering the state of hybridization of carbon atoms, find out the molecule
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply