| ⇦ | 
| ⇨ |
How many coulombs are required for the oxidation of 1 mole H₂O to O₂
Options
(a) 3.86 x 10⁵ C
(b) 1.93 x 10⁵ C
(c) 4.825 x 10⁴ C
(d) 9.65 x 10⁴ C
Correct Answer:
1.93 x 10⁵ C
Explanation:
H₂O → H₂ + 1/2 O₂ mole. No. of electrons involved = 2 mole = 2 × 6.023 × 10²³. 1 mole of electronic charge = 96500 C. ⇒ 2 mole of electronic charge = 2 × 96500. = 1.93 × 10⁵ C.
Related Questions: - Dinitrogen and dioxygen are main constituents of air but these do not react
- ‘Metals are usually not found as nitrates in their ores”. Out of the following two
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
- A physician wishes to prepare a buffer solution at pH = 3.85
- The shape of benzene is
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Dinitrogen and dioxygen are main constituents of air but these do not react
- ‘Metals are usually not found as nitrates in their ores”. Out of the following two
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
- A physician wishes to prepare a buffer solution at pH = 3.85
- The shape of benzene is
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply