| ⇦ | 
| ⇨ |
H₂O₂ reduces MnO₄⁻ ion to
Options
(a) Mn³⁺
(b) Mn²⁺
(c) Mn⁻
(d) Mn⁺
Correct Answer:
Mn²⁺
Explanation:
2MnO₄⁻ + 5H₂O₂ + 6H⁺ → 2Mn²⁺ + 8H₂O + 5O₂. Thus in this reaction, H₂O₂ reduces the MnO₄⁻ ion to Mn²⁺ ion.
Related Questions: - If the value of an equilibrium constant for a particular reaction is 1.6 ˣ 10¹²,
- Malachite is an ore of
- In which one of the following is not a buffer solution
- For the reaction , X₂O₄(l) → 2XO₂(g), ΔG is
- The total number of electrons present in all the p-orbitals of bromine is
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the value of an equilibrium constant for a particular reaction is 1.6 ˣ 10¹²,
- Malachite is an ore of
- In which one of the following is not a buffer solution
- For the reaction , X₂O₄(l) → 2XO₂(g), ΔG is
- The total number of electrons present in all the p-orbitals of bromine is
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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