Four diatomic species are listed below. Identilfy the correct order in which

Four Diatomic Species Are Listed Below Identilfy The Correct Order Chemistry Question

Four diatomic species are listed below. Identilfy the correct order in which the bond order is increasing in them:

Options

(a) NO < O₂⁻ < C₂²⁻ < He₂⁺
(b) O₂⁻ < NO < C₂²⁻ < He₂⁺
(c) C₂²⁻ < He₂⁺ < O₂⁻ < NO
(d) He₂⁺ < O₂⁻ < NO < C₂²⁻

Correct Answer:

He₂⁺ < O₂⁻ < NO < C₂²⁻

Explanation:

Bond order = Nₙ – Nₘ / 2
He₂⁺ = σ(1s)² σ*(1s) B.O. = 0.5
O₂⁻ = KKσ(2s)² σ*(2s)² σ(2pₖ)²
π(2pᵢ)² π(2pⱼ)² π*(2pᵢ)² π*(2pⱼ)¹ B.O. = 1.5
NO = KKσ(2s)² σ*(2s)²π(2pᵢ)²
π(2pⱼ)² σ(2pₖ)² π*(2pᵢ)¹ B.O. = 2.5
C₂²⁻ = KKσ(2s)² σ*(2s)²π(2pᵢ)² π(2pⱼ)² σ(2pₖ)² B.O. = 3.0

Related Questions:

  1. For a spontaneous process, entropy always
  2. 1.0g of magnesium is burnt with 0.56 g O₂ in a closed vessel
  3. In HS⁻, I⁻, R-NH₂, NH₃ order of proton accepting tendency will be
  4. For a reversible reaction, if we increase concentration of the reactants,
  5. Which of the following gas is called rare gas

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*