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For which one of the following sets of four quantum numbers, an electron will have the highest energy?n=3, l=2, m=1, s=1/2
Options
(a) n=4, l=2, m=-1, s=1/2
(b) n=4, l=1, m=0, s=-1/2
(c) n=5, l=0, m=0, s=-1/2
(d) n=4, l=2, m=-1, s=1/2
Correct Answer:
n=4, l=1, m=0, s=-1/2
Explanation:
The sub-shell are 3d, 4d, 4p and 4s, 4d has highest energy as n + l value is maximum for this.
Related Questions: - Oxidation number of Fe in Fe₃O₄ is
- Amino acid leucine is
- An orbital in which n = 4 and l = 2 is expressed by
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Oxidation number of Fe in Fe₃O₄ is
- Amino acid leucine is
- An orbital in which n = 4 and l = 2 is expressed by
- A flask contains 36% oxtgen and 26% hydrogen. If the total pressure of the mixture
- The number of unpaired electron in Mn²⁺ is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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