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For the normal eye, the cornea of eye provides a converging power of 40D and the least converging power of the eye lens behind the cornea is 20D. Using this information, the distance between the retina and the eye lens of the eye can be estimated to be:
Options
(a) 2.5 cm
(b) 1.67 cm
(c) 1.5 cm
(d) 5 cm
Correct Answer:
2.5 cm
Explanation:
1/f = 1/v – 1/u
= 1/ 1 / 40 = 1/u
u = 1/40 m = 2.5 m
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The resultant of two forces, one double the other in magnitude, is perpendicular
- A particle is under two mutually perpendicular simple harmonic motions
- If v is the speed of sound in air, then the shortest length of the closed pipe
- A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
- A vibration magnetometer placed in magnetic meridian has a small bar magnet
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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