| ⇦ | 
| ⇨ |
For the normal eye, the cornea of eye provides a converging power of 40D and the least converging power of the eye lens behind the cornea is 20D. Using this information, the distance between the retina and the eye lens of the eye can be estimated to be:
Options
(a) 2.5 cm
(b) 1.67 cm
(c) 1.5 cm
(d) 5 cm
Correct Answer:
2.5 cm
Explanation:
1/f = 1/v – 1/u
= 1/ 1 / 40 = 1/u
u = 1/40 m = 2.5 m
Related Questions: - A tuned amplifier circuit is used to generate a carrier frequency of 2 MHz
- A body rolls down a stair case of 5 steps. Each step has height 0.1 m and width 0.1m
- A capacitor of capacitance value 1 μF is charged to 30 V and the battery
- Weber ampere per metre is equal to
- 6Ω and 12Ω resistors are connected in parallel. This combination is connected
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A tuned amplifier circuit is used to generate a carrier frequency of 2 MHz
- A body rolls down a stair case of 5 steps. Each step has height 0.1 m and width 0.1m
- A capacitor of capacitance value 1 μF is charged to 30 V and the battery
- Weber ampere per metre is equal to
- 6Ω and 12Ω resistors are connected in parallel. This combination is connected
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply