For the equilibrium, H₂O(l) ⇌ H₂O(g) at 1 atm and 298 K,

For The Equilibrium Hol Hog At 1 Atm And Chemistry Question

For the equilibrium, H₂O(l) ⇌ H₂O(g) at 1 atm and 298 K,

Options

(a) standard free energy change is equal to zero (ΔG⁰ = 0)
(b) free energy change is less then zero (ΔG⁰ < 0)
(c) standard free energy change is less then zero (ΔG⁰ < 0)
(d) standard free energy change is greater then zero (ΔG⁰ > 0)

Correct Answer:

free energy change is less then zero (ΔG⁰ < 0)

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. In the silver plating of copper, K[Ag(CN)₂] is used instead of AgNO₃. The reason
  2. Atoms in a P₄ molecule of white phosphorus are arranged regularly in the follow
  3. Indicator used in the titration of oxalic acid and NaOH is
  4. The compound which does not exist as hydrate form
  5. There are two containers containing gases,one at pressure 30 atm and volume

Topics: Equilibrium (104)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*