| ⇦ | 
| ⇨ |
For the equilibrium, H₂O(l) ⇌ H₂O(g) at 1 atm and 298 K,
Options
(a) standard free energy change is equal to zero (ΔG⁰ = 0)
(b) free energy change is less then zero (ΔG⁰ < 0)
(c) standard free energy change is less then zero (ΔG⁰ < 0)
(d) standard free energy change is greater then zero (ΔG⁰ > 0)
Correct Answer:
free energy change is less then zero (ΔG⁰ < 0)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - On doubling P and V with constant temperature the equilibrium constant will
- Mass of 0.1 mole of methane is
- The elements with atomic number 9,17,35,53,85 are called
- What is the equivalent weight of SnCl₂ in the following reaction
- An aqueous solution of sodium sulphate is electrolysed using inert electrodes
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- On doubling P and V with constant temperature the equilibrium constant will
- Mass of 0.1 mole of methane is
- The elements with atomic number 9,17,35,53,85 are called
- What is the equivalent weight of SnCl₂ in the following reaction
- An aqueous solution of sodium sulphate is electrolysed using inert electrodes
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply