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For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is
Options
(a) (1/2)
(b) 1/√2
(c) 2
(d) √2
Correct Answer:
(1/2)
Explanation:
-GMm/R² + mω²R = 0
GMm/R² = mω²R
Kinetic Energy = 1/2Iω²
KE= 1/2mR²ω² = GMm/2R
Potential energy = -GMm/R
Therefore, Kinetic energy = |Potential energy|/2
Kinetic energy/|Potential energy| = 1/2.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Bragg’s law for X-rays is
- The cylindrical tube of a spray pump has radius R, one end of which has n fine holes,
- A boy standing at the top of a tower of 20m height drops a stone
- A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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