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Equivalent weight of KMnO₄ in basic medium is (mol.wt. of KMnO₄ = 158)
Options
(a) 31.5
(b) 52.67
(c) 79
(d) 158
Correct Answer:
52.67
Explanation:
MnO₄⁻ + 2H₂O + 3e⁻ → MnO₂ + 4OH⁻
Equivalent weight = molecular weight / 3.
The oxidation number changes from +7 to +4. so , Equivalent weight = 158/3 = 52.67.
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Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Nitrogen in an organic compound can be estimate by
- Oxidation numbers of carbon in CH₂Cl₂,CO₂ and CO₃²⁻ are respectively
- Standard enthalpy of vaporisation Δvap H⁰ for water at 100⁰C is 40.66 kJ mol⁻¹.
- Formula of Plaster of Paris is
- The oxidation of benzene by V₂O₅ in the presence of air produces
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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