| ⇦ |
| ⇨ |
Equivalent weight of KMnO₄ in basic medium is (mol.wt. of KMnO₄ = 158)
Options
(a) 31.5
(b) 52.67
(c) 79
(d) 158
Correct Answer:
52.67
Explanation:
MnO₄⁻ + 2H₂O + 3e⁻ → MnO₂ + 4OH⁻
Equivalent weight = molecular weight / 3.
The oxidation number changes from +7 to +4. so , Equivalent weight = 158/3 = 52.67.
Related Questions: - Which of the following statements is true for the electrochemical Daniel cell
- In which of the following resonance will be possible
- Which of the following does not participate in Solvey’s process for the formation
- The alkali halide that is soluble in pyridine is
- Acetamide and ethylamine can be distinguished by reacting with
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following statements is true for the electrochemical Daniel cell
- In which of the following resonance will be possible
- Which of the following does not participate in Solvey’s process for the formation
- The alkali halide that is soluble in pyridine is
- Acetamide and ethylamine can be distinguished by reacting with
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply