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Equal volumes of methanoic acid and sodium hydroxide are mixed, if x is the heat of formation of water, then heat evolved on neutralisation is
Options
(a) twice of x
(b) equal to x
(c) more than x
(d) less than x
Correct Answer:
less than x
Explanation:
“Methanoic acid(HCOOH), Sodium hydroxide(NaOH). Weak acid and strong base neutralisation. H⁺ + OH⁻ → H₂O + x(Heat of formation),
HCOOH ⇌ HCOO⁻ + H⁺, NaOH ⇌ Na⁺ + OH⁻,
H⁺ + OH⁻ ⇌ H₂O + Less than x (Heat of reaction). Because, some of the energy is lost in ionization of weak acid, HCOOH.”.
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- Carbon atom in C₂(CN)₄ are
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Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What will be the correct relationship between free energy and equilibrium constant K
- Carbon atom in C₂(CN)₄ are
- Which of the following represents correct decreasing order of polarity?
- 0.4g of silver salt of a monobasic organic acid gave 0.26g pure silver on ignition
- A device that converts energy of combustion of fuels like hydrogen and methane,
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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