⇦ | ⇨ |
Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - In the softening of the water by passing it through cationic and anionic exchang
- Which of the following is the IUPAC name of the compound
- A unit cell of sodium chloride has four formula units.The edge length of the unit cell
- The pH value of the solution in which a particular amino acid dose not migrate
- Main constituents of LPG is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the softening of the water by passing it through cationic and anionic exchang
- Which of the following is the IUPAC name of the compound
- A unit cell of sodium chloride has four formula units.The edge length of the unit cell
- The pH value of the solution in which a particular amino acid dose not migrate
- Main constituents of LPG is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply