| ⇦ |
| ⇨ |
Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - A compound with empirical formula CH₂O has a vapour density of 30.Its molecular
- Which of the following statements is not true about alcohols
- Carborundum is
- In SN2 reaction the sequence of bond breaking and bond formation is as follows
- Which one of the following compounds on nitration easily produces nitro derivative
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A compound with empirical formula CH₂O has a vapour density of 30.Its molecular
- Which of the following statements is not true about alcohols
- Carborundum is
- In SN2 reaction the sequence of bond breaking and bond formation is as follows
- Which one of the following compounds on nitration easily produces nitro derivative
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply