| ⇦ | 
| ⇨ |
Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - which of the following oxy acids of phosphorus is a reducing agent and monobasic
- Which one of the alkali metals, forms only, the normal oxide, M₂O on heating
- The property of crystalline solid is not
- 6.4 g SO₂ at 0⁰C and 0.99 atm pressure occupies a volume of 2.24 L
- Amino acid leucine is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- which of the following oxy acids of phosphorus is a reducing agent and monobasic
- Which one of the alkali metals, forms only, the normal oxide, M₂O on heating
- The property of crystalline solid is not
- 6.4 g SO₂ at 0⁰C and 0.99 atm pressure occupies a volume of 2.24 L
- Amino acid leucine is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply