| ⇦ | 
| ⇨ |
Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - Change in enthalpy for reaction,2H₂O₂ → 2H₂O + O₂
- What is the equivalent weight of SnCl₂ in the following reaction
- First ionization potential of Mg is
- An example of amino acid containing benzene ring is
- Which of the following will exhibit maximum ionic conductivity?
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Change in enthalpy for reaction,2H₂O₂ → 2H₂O + O₂
- What is the equivalent weight of SnCl₂ in the following reaction
- First ionization potential of Mg is
- An example of amino acid containing benzene ring is
- Which of the following will exhibit maximum ionic conductivity?
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply