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Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - What is the number of mols of hydrogen atoms in 3.2g of methane
- The hybridised state of N in R₂NH is
- Solubility of MX₂ – type electrolytes is 0.5 ˣ 10⁻⁴ mol/L.,
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Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the number of mols of hydrogen atoms in 3.2g of methane
- The hybridised state of N in R₂NH is
- Solubility of MX₂ – type electrolytes is 0.5 ˣ 10⁻⁴ mol/L.,
- Boron is unable to form BF₆³⁻ because of
- Which of the following is an alicyclic compound
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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