⇦ | ⇨ |
Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - Which one of the following is antimalarial drug
- Which statement is correct
- The correct order of ionisation energy for comparing carbon, nitrogen and oxygen
- Which of the following does not have a metal-carbon bond
- Reaction of nitrous acid with aliphatic primary amine will give
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following is antimalarial drug
- Which statement is correct
- The correct order of ionisation energy for comparing carbon, nitrogen and oxygen
- Which of the following does not have a metal-carbon bond
- Reaction of nitrous acid with aliphatic primary amine will give
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply