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Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
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Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For decolourization of 1 mole of KMnO₄, the moles of H₂O₂ required is
- A drug that is antipyretic as well as analgesic is
- Nitrogen dioxide and sulphur dioxide have some properties in common.
- For the cell reactionCu²⁺ (C₁.aq) + Zn(s) = Zn²⁺(C₂.aq ) + Cu(s)
- The complex [Co(NH₃)₅Br]²⁺ SO₄²⁻ and [Co(NH₃)₅SO₄]⁺ Br⁻ are
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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