⇦ | ⇨ |
Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - Among the following the compound that is readily soluble in water is
- MnO₂ and H₂O added to Nacl, the greenish-yellow gas liberate is
- In acetylene molecule, the two carbon atoms are linked by
- A no. of ionic compounds, e.g., AgCl, CaF₂, BaSO₄ are insoluable in water
- On doubling P and V with constant temperature the equilibrium constant will
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Among the following the compound that is readily soluble in water is
- MnO₂ and H₂O added to Nacl, the greenish-yellow gas liberate is
- In acetylene molecule, the two carbon atoms are linked by
- A no. of ionic compounds, e.g., AgCl, CaF₂, BaSO₄ are insoluable in water
- On doubling P and V with constant temperature the equilibrium constant will
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply