| ⇦ | 
| ⇨ |
Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - Chlorine is in +1 oxidation state in which of the following
- 0.4g of silver salt of a monobasic organic acid gave 0.26g pure silver on ignition
- Which one of the following is not a sulphide ore
- Which one of the following is the heaviest
- For distinguishing phenol and acetic acid we required to react (treat) them
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Chlorine is in +1 oxidation state in which of the following
- 0.4g of silver salt of a monobasic organic acid gave 0.26g pure silver on ignition
- Which one of the following is not a sulphide ore
- Which one of the following is the heaviest
- For distinguishing phenol and acetic acid we required to react (treat) them
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply