| ⇦ |
| ⇨ |
Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - The plot of concentration of the reactant vs time for a reaction is a straight
- For the cell reactionCu²⁺ (C₁.aq) + Zn(s) = Zn²⁺(C₂.aq ) + Cu(s)
- In Dumas’ method of estimation of nitrogen 0.35g of an organic compound gave 55mL
- What is the volume of ’20 volume H₂O₂. required to get 5000 cm³ of oxygen at STP?
- Allergy is the state in which a person experiences
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The plot of concentration of the reactant vs time for a reaction is a straight
- For the cell reactionCu²⁺ (C₁.aq) + Zn(s) = Zn²⁺(C₂.aq ) + Cu(s)
- In Dumas’ method of estimation of nitrogen 0.35g of an organic compound gave 55mL
- What is the volume of ’20 volume H₂O₂. required to get 5000 cm³ of oxygen at STP?
- Allergy is the state in which a person experiences
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply