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Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-ray tube. The cut-off wavelength (λ₀) of the emitted X-ray is
Options
(a) λ₀= 2mcλ²/h
(b) λ₀= 2h/mc
(c) λ₀= 2m²c²λ³/h²
(d) λ₀= λ
Correct Answer:
λ₀= 2mcλ²/h
Explanation:
λ = h / p ⇒ p = h / λ
KE of electrons = E = p² / 2m = h² / 2mλ²
Also in X-ray, λ₀ = hc / E = 2mcλ² / h
Related Questions: - A transformer of 100% efficiency has 200 turns in the primary coil and 40000 turns
- Which one of the following statements is WRONG in the context of X-rays generated
- A wire of length 2 m is made from 10 cm³ of copper. A force F is applied so that
- A projectile is thrown in the upward direction making an angle of 60°with the horizontal
- The intermediate image formed by the objective of a compound microscope is
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A transformer of 100% efficiency has 200 turns in the primary coil and 40000 turns
- Which one of the following statements is WRONG in the context of X-rays generated
- A wire of length 2 m is made from 10 cm³ of copper. A force F is applied so that
- A projectile is thrown in the upward direction making an angle of 60°with the horizontal
- The intermediate image formed by the objective of a compound microscope is
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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