⇦ | ⇨ |
Consider 3rd orbit of He⁺(helium), using non-relativistic approach, the speed of electron in this orbit will be (given K=9×10⁹ constant, Z=2 and h=6.6×10⁻³⁴ J-s)
Options
(a) 2.92×10⁶ ms⁻¹
(b) 1.46×10⁶ ms⁻¹
(c) 0.73×10⁶ ms⁻¹
(d) 3×10⁶ ms⁻¹
Correct Answer:
1.46×10⁶ ms⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle moves with constant speed v along a circular path of radius r and completes
- When a metallic surface is illuminated with radiation of wavelength λ,
- Which one of the following bonds produces a solid that reflects light in the visible region
- The respective speeds of the molecules are 1,2,3,4 and 5 km/s.
- A proton and an alpha particle both enter a region of uniform magnetic field B,
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves with constant speed v along a circular path of radius r and completes
- When a metallic surface is illuminated with radiation of wavelength λ,
- Which one of the following bonds produces a solid that reflects light in the visible region
- The respective speeds of the molecules are 1,2,3,4 and 5 km/s.
- A proton and an alpha particle both enter a region of uniform magnetic field B,
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply