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Boron has two stable isotopes, ¹°B(19%) and ¹¹B(81%). Average atomic weight for boron in the periodic table is
Options
(a) 10.8
(b) 10.2
(c) 11.2
(d) 10
Correct Answer:
10.8
Explanation:
Avg Atomic Mass = (RA1 x MN1 + RA2 x MN2) / (RA1+ RA2)
Where RA= Relative Abundance, MN= Mass Number
= 19 x 10 + 81 x 11 / 100 = 10.81
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Question Type: Memory
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Difficulty Level: Easy
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Topics: Basic Concepts of Chemistry
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Subject: Chemistry
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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