⇦ | ⇨ |
Boron has two stable isotopes, ¹°B(19%) and ¹¹B(81%). Average atomic weight for boron in the periodic table is
Options
(a) 10.8
(b) 10.2
(c) 11.2
(d) 10
Correct Answer:
10.8
Explanation:
Avg Atomic Mass = (RA1 x MN1 + RA2 x MN2) / (RA1+ RA2)
Where RA= Relative Abundance, MN= Mass Number
= 19 x 10 + 81 x 11 / 100 = 10.81
Related Questions: - Magnetic moment 2.83 BM is given by which of the following ions
- Standard enthalpy and standard entropy changes for the oxidation of ammonia
- In the periodic table, the element with atomic number 16 will be placed
- Among the given compounds, one which can be distinguished by AgNO₃ is
- For the reaction 2SO₃(g) → 2SO₂(g) + O₂(g) the entropy change (ΔG) is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Magnetic moment 2.83 BM is given by which of the following ions
- Standard enthalpy and standard entropy changes for the oxidation of ammonia
- In the periodic table, the element with atomic number 16 will be placed
- Among the given compounds, one which can be distinguished by AgNO₃ is
- For the reaction 2SO₃(g) → 2SO₂(g) + O₂(g) the entropy change (ΔG) is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply