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At S.T.P the density of CCl₄ vapours in g/L will be nearest to
Options
(a) 6.87
(b) 3.42
(c) 10.26
(d) 4.57
Correct Answer:
6.87
Explanation:
Molecular Weight of CCl₄ = 35.5 + 12 x 4 = 154
1 mole CCl₄ vapour=154 g
According to Avogadro’s hypothesis we know that the molar volume of a gas at STP is 22.4 litres
= 154/22.4 = 6.87
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The minimum amount of energy required for the reacting molecules to undergo
- A mixture contains O₂ and N₂ in the ratio of 1 : 4 by the weight
- The maximum number of molecules is present in
- At what temperature will the volume of gas becomes 2x, if volume
- In Kjeldahl’s mathod, the nitrogen present is estimated as
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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