| ⇦ | 
| ⇨ |
At place on earth, the vertical component of earth’s magnetic field is √3 times its horizontal component. The angle of dip at this place is …….
Options
(a) 60⁰
(b) 30⁰
(c) 45⁰
(d) 0⁰
Correct Answer:
60⁰
Explanation:
As vertical component of Earth’s magnetic field is Bᵥ = √3 Bʜ
Angle of dip at any place is a given by, tan δ = Bᵥ / Bʜ = Bᵥ = √3 Bʜ / Bʜ = √3
Then, δ = tan⁻¹ (√3) = 60⁰
Related Questions: - When the speed of electron beam used in Young’s double slit experiment is increased,
- A body starts from rest, what is the ratio of the distance travelled by the body
- A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds.
- A nucleus of mass number 220, initially at rest, emits an α-particle. If the Q-value
- A wire of length 1 m is placed in a uniform magnetic field of 1.5 tesla at an angle
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When the speed of electron beam used in Young’s double slit experiment is increased,
- A body starts from rest, what is the ratio of the distance travelled by the body
- A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds.
- A nucleus of mass number 220, initially at rest, emits an α-particle. If the Q-value
- A wire of length 1 m is placed in a uniform magnetic field of 1.5 tesla at an angle
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply