| ⇦ | 
| ⇨ |
At 27⁰C average kinetic energy of one mole of helium gas can be given
Options
(a) 3741.30 J mol⁻¹
(b) 374.13 J mol⁻¹
(c) 1662.8 J mol⁻¹
(d) 166.28 J mol⁻¹
Correct Answer:
3741.30 J mol⁻¹
Explanation:
The average kinetic energy per mole does not depend on the nature of the gas but depends only on temperature. Average Kinetic energy per mole = 3 / 2 RT. given, T = 27⁰C = 273 + 27 = 300 K. R = 8.314 JK⁻¹ mol ⁻¹ ⇒ K.E = 3/2 x 8.314 x 300 = 3741.3 J mol ⁻¹.
Related Questions: - Which of the following species contains equal number of σ- and π-bonds
- By which of the following processes permanent hardness of water can be removed
- A corked flask containing boiling water and its vapour is allowed
- Which of the following is the strongest base
- Which of the following elements will have the lowest first ionisation energy?
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following species contains equal number of σ- and π-bonds
- By which of the following processes permanent hardness of water can be removed
- A corked flask containing boiling water and its vapour is allowed
- Which of the following is the strongest base
- Which of the following elements will have the lowest first ionisation energy?
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply