| ⇦ |
| ⇨ |
At 27⁰C average kinetic energy of one mole of helium gas can be given
Options
(a) 3741.30 J mol⁻¹
(b) 374.13 J mol⁻¹
(c) 1662.8 J mol⁻¹
(d) 166.28 J mol⁻¹
Correct Answer:
3741.30 J mol⁻¹
Explanation:
The average kinetic energy per mole does not depend on the nature of the gas but depends only on temperature. Average Kinetic energy per mole = 3 / 2 RT. given, T = 27⁰C = 273 + 27 = 300 K. R = 8.314 JK⁻¹ mol ⁻¹ ⇒ K.E = 3/2 x 8.314 x 300 = 3741.3 J mol ⁻¹.
Related Questions: - Which of the following hydrogen bonds are strongest in vapour phase
- How many calories are required to heat 40 gram of argon from 40⁰C to 100⁰C
- Which of the following is electron-deficient?
- In Cr₂O₇²⁻ the oxidation numbers are
- The pressure and temperature of 4 dm³ of carbon dioxide gas are doubled
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following hydrogen bonds are strongest in vapour phase
- How many calories are required to heat 40 gram of argon from 40⁰C to 100⁰C
- Which of the following is electron-deficient?
- In Cr₂O₇²⁻ the oxidation numbers are
- The pressure and temperature of 4 dm³ of carbon dioxide gas are doubled
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply