| ⇦ |
| ⇨ |
At 27⁰C average kinetic energy of one mole of helium gas can be given
Options
(a) 3741.30 J mol⁻¹
(b) 374.13 J mol⁻¹
(c) 1662.8 J mol⁻¹
(d) 166.28 J mol⁻¹
Correct Answer:
3741.30 J mol⁻¹
Explanation:
The average kinetic energy per mole does not depend on the nature of the gas but depends only on temperature. Average Kinetic energy per mole = 3 / 2 RT. given, T = 27⁰C = 273 + 27 = 300 K. R = 8.314 JK⁻¹ mol ⁻¹ ⇒ K.E = 3/2 x 8.314 x 300 = 3741.3 J mol ⁻¹.
Related Questions: - The enthalphy change for the reaction N₂ + 3H₂ → 2NH₃ is -92.38 kJ at 298K
- One of the following that cannot undergo dehydrohalogenation is
- Which of the following order is wrong?
- Ethyl alcohol exhibits acidic character on reacting with
- Two different gases enclosed in different flasks A and B at same temperature and pressure
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The enthalphy change for the reaction N₂ + 3H₂ → 2NH₃ is -92.38 kJ at 298K
- One of the following that cannot undergo dehydrohalogenation is
- Which of the following order is wrong?
- Ethyl alcohol exhibits acidic character on reacting with
- Two different gases enclosed in different flasks A and B at same temperature and pressure
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply