| ⇦ |
| ⇨ |
At 27⁰C average kinetic energy of one mole of helium gas can be given
Options
(a) 3741.30 J mol⁻¹
(b) 374.13 J mol⁻¹
(c) 1662.8 J mol⁻¹
(d) 166.28 J mol⁻¹
Correct Answer:
3741.30 J mol⁻¹
Explanation:
The average kinetic energy per mole does not depend on the nature of the gas but depends only on temperature. Average Kinetic energy per mole = 3 / 2 RT. given, T = 27⁰C = 273 + 27 = 300 K. R = 8.314 JK⁻¹ mol ⁻¹ ⇒ K.E = 3/2 x 8.314 x 300 = 3741.3 J mol ⁻¹.
Related Questions: - If pH of A,B,C and D are 9.5, 2.5,3.5 and 5.5 respectively, then strongest acid is
- Which one of the following compounds on nitration easily produces nitro derivative
- The amphoteric oxide is
- The total number of isomeric alcohols with the molecular formula C₄H₉OH is
- A sp³ – hybrid orbital contains
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If pH of A,B,C and D are 9.5, 2.5,3.5 and 5.5 respectively, then strongest acid is
- Which one of the following compounds on nitration easily produces nitro derivative
- The amphoteric oxide is
- The total number of isomeric alcohols with the molecular formula C₄H₉OH is
- A sp³ – hybrid orbital contains
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply