Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85g

Assuming Fully Decomposed The Volume Of Co Released At Stp Chemistry Question

Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85 g of BaCO₃(Atomic mass Ba=137) will be

Options

(a) 2.24 L
(b) 4.96 L
(c) 1.12L
(d) 0.84L

Correct Answer:

1.12L

Explanation:

BaCO₃ → BaO+ CO₂
Atomic Mass of Ba=137
Atomic Mass of C=12
Atomic Mass of O=16
Molecular Mass of BaCO₃ = 137 + 12 + (16*3) = 197
197 gm of BaCO₃ released carbondioxide = 22.4 litre at STP
1 gm of BaCO₃ released carbondioxide = 22.4/197 litre
9.85 gm of BaCO₃ released carbondioxide = 22.4/197 x 9.85 = 1.12 litre

Related Questions:

  1. 100 mL of HCl + 35 mL of NaOH, colour of methyl orange in the solution will be
  2. Boron has two stable isotopes, ¹°B(19%) and ¹¹B(81%). Average atomic weight
  3. A mixture of potassium chlorate, oxalic acid and sulphuric acid is heated.
  4. The absorption of hydrogen by palladium is called
  5. Which is not correct

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*