⇦ | ⇨ |
Aperture of human eye is 0.2 cm. The minimum magnifying power of a visual telescope, whose objective has diameter 100 cm is
Options
(a) 500
(b) 0.002
(c) 0.02
(d) 100
Correct Answer:
500
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - As a result of interference of two coherent sources of light, energy is
- A source of sound S emitting waves of frequency 100 Hz and an observer
- The second overtone of an open pipe is in resonance with the first overtone
- The voltage gain of an amplifier with 9% negative feedback is 10.
- Two identical charges repel each other with a force equal to 10 mgwt they are 0.6 m
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- As a result of interference of two coherent sources of light, energy is
- A source of sound S emitting waves of frequency 100 Hz and an observer
- The second overtone of an open pipe is in resonance with the first overtone
- The voltage gain of an amplifier with 9% negative feedback is 10.
- Two identical charges repel each other with a force equal to 10 mgwt they are 0.6 m
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply