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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is the function of the step-up transformer?
- Surface tension of water will be minimum at
- The kinetic energy of α-particle emitted in the α-dacay of ₈₈Ra²²⁶ is
- Angle of contact of a liquid with a solid depends on
- Two forces of magnitude 8N and 15N respectively act at a point so as to make the resultant force
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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