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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves along the x-axis such that its co-ordinate (x) varies with time (t)
- Einstein’s photoelectric equation is
- The instantaneous angular position of a point on a rotating wheel is given by
- An inclined plane of length 5.60m making an angle of 45⁰ with the horizontal is placed
- When a magnet is taken towards a coil, the induced e.m.f. depends on
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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