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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- The phase difference between the instantaneous velocity and acceleration of a particle
- A force of 10 newton acts on a body of mass 20 kg for 10 seconds. Change in its momentum
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
- A geostationary satellite is orbiting the earth at a height of 5R above that surface
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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