| ⇦ | 
| ⇨ |
An organic compound contains 49.3% carbon, 6.84% hydrogen and its vapour density is 73. Molecular formula of the compound is
Options
(a) C₃H₈O₂
(b) C₃H₁₀O
(c) C₆H₉O
(d) C₆H₁₀O₄
Correct Answer:
C₆H₁₀O₄
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In the photo-electron emission,the energy of the emitted electron is
- Amines behave as
- In pressure cooker food is made faster because
- In Dumas’ method of estimation of nitrogen 0.35g of an organic compound gave 55mL
- In an exothermic reaction(reversible) which of the following has positive value
Topics: Basic Principles of Organic Chemistry
(124)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the photo-electron emission,the energy of the emitted electron is
- Amines behave as
- In pressure cooker food is made faster because
- In Dumas’ method of estimation of nitrogen 0.35g of an organic compound gave 55mL
- In an exothermic reaction(reversible) which of the following has positive value
Topics: Basic Principles of Organic Chemistry (124)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply