| ⇦ | 
| ⇨ |
An observer moving away from a stationary source. The observed frequency is half of the emitted frequencies. The velocity of observer is (c=speed of sound in air)
Options
(a) c
(b) c/2
(c) c/3
(d) 2c
Correct Answer:
c/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - For a given velocity, a projectile has the same range R for two angles of projection.
- Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance
- A juggler maintains four balls in motion,making each of them to rise
- A spring when stretched by 2mm containing energy 4 J. If it is stretched
- If A=4i+4j+4k and b=3i+j+4k, then angle between vectors A and B is
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a given velocity, a projectile has the same range R for two angles of projection.
- Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance
- A juggler maintains four balls in motion,making each of them to rise
- A spring when stretched by 2mm containing energy 4 J. If it is stretched
- If A=4i+4j+4k and b=3i+j+4k, then angle between vectors A and B is
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply