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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In the adiabatic compression, the decrease in volume associated with
- The charges Q, +q, and +q are placed at the vartices of an equilateral
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the adiabatic compression, the decrease in volume associated with
- The charges Q, +q, and +q are placed at the vartices of an equilateral
- Heat produced in a resistance according to which law?
- A particle performing uniform circular motion has angular momentum
- The force of repulsion between two electrons at a certain distance is F.
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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