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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
- The mass of a lift is 2000kg. When the tension in the supporting cable is 28000N, then its acceleration is
- Which is incorrect about thermal process
- When 10¹⁹elecrons are removed from a neutral metal plate through some process,
- What is the dimension of impedance?
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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