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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of length 1 m is placed in a uniform magnetic field of 1.5 tesla at an angle
- As per Bohr model, the minimum energy (in eV) required to remove an electron
- Two bodies A and B have masses 20 Kg and 5 Kg respectively. Each one is acted
- In common base circuit of a transistor, current amplification factor is 0.95.
- The moment of inertia of a rod about an axis through its centre and perpendicular
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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