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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An ideal black body is equivalent to
- A circular road of radius 1000m has banking angle 45°.The maximum safe speed of a car
- A body of mass 0.25 kg is projected with muzzle velocity 100 m/s from a tank
- A proton beam enters a magnetic field of 10⁻⁴ Wb/m² normally. If the specific charge
- Four point masses, each of value m, are placed at the corners of a square ABCD
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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