| ⇦ | 
| ⇨ |
An interference pattern was made by using red light. If the red light is replaced by blue light, the fringes will becomes
Options
(a) Wider
(b) Narrower
(c) Fainter
(d) Brighter
Correct Answer:
Narrower
Explanation:
Fringe width β = λD / d
β(ʀed) / β(ʙlue) = λ(ʀed) / λ(ʙlue)
λ(ʙlue) is < λ(ʀed)
Therefore, Fringe width with blue light < β with red light.
Fringes become narrower with blue light.
Related Questions: - A 10 micro farad capacitor is charged to 500 V and then its plates are joined
- An a.c. supply gives 30 volt r.m.s which passes through a 10Ω resistance.
- The device can act as a complete electronic circuit is
- If a charge in current of 0.01 A in one coil produces a change in magnetic flux
- A body initially at rest is moving with uniform acceleration a m/s²
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 10 micro farad capacitor is charged to 500 V and then its plates are joined
- An a.c. supply gives 30 volt r.m.s which passes through a 10Ω resistance.
- The device can act as a complete electronic circuit is
- If a charge in current of 0.01 A in one coil produces a change in magnetic flux
- A body initially at rest is moving with uniform acceleration a m/s²
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply