| ⇦ | 
| ⇨ |
An interference pattern was made by using red light. If the red light is replaced by blue light, the fringes will becomes
Options
(a) Wider
(b) Narrower
(c) Fainter
(d) Brighter
Correct Answer:
Narrower
Explanation:
Fringe width β = λD / d
β(ʀed) / β(ʙlue) = λ(ʀed) / λ(ʙlue)
λ(ʙlue) is < λ(ʀed)
Therefore, Fringe width with blue light < β with red light.
Fringes become narrower with blue light.
Related Questions:
- Zenor breakdown will occur if
- A closely wound solenoid of 2000 turns and area of cross-section 1.5 x 10⁻⁴ m² carries
- A bar magnet of moment of inertia I is vibrated in a magnetic field of induction
- A charge Q is uniformly distributed over a large plastic plate. The electric field
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply