| ⇦ |
| ⇨ |
An interference pattern was made by using red light. If the red light is replaced by blue light, the fringes will becomes
Options
(a) Wider
(b) Narrower
(c) Fainter
(d) Brighter
Correct Answer:
Narrower
Explanation:
Fringe width β = λD / d
β(ʀed) / β(ʙlue) = λ(ʀed) / λ(ʙlue)
λ(ʙlue) is < λ(ʀed)
Therefore, Fringe width with blue light < β with red light.
Fringes become narrower with blue light.
Related Questions: - A particle moving in a straight line covers half the distance with speed of 3 m/s
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- A road of width 20 m forms an arc of radius 15 m,its outer edge is 2m higher than
- Charge q is uniformly spread on a thin ring of radius R. The ring rotates
- To draw the maximum current from a combination of cells, how should be the cells
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moving in a straight line covers half the distance with speed of 3 m/s
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- A road of width 20 m forms an arc of radius 15 m,its outer edge is 2m higher than
- Charge q is uniformly spread on a thin ring of radius R. The ring rotates
- To draw the maximum current from a combination of cells, how should be the cells
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply