⇦ | ![]() | ⇨ |
An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62⁰C, its efficiency is doubled. Temperature of the source is
Options
(a) 37⁰C
(b) 62⁰C
(c) 99⁰C
(d) 124⁰C
Correct Answer:
99⁰C
Explanation:
Since efficiency of engine is ? = 1 – T₂ / T₁
According to the problem, 1/6 = 1 – T₂ / T₁ ……(1)
When the temperature of the sink is reudced by 62⁰C, its efficiency is doubled
2 (1/6) = 1 – T₂ – 62 / T₁ ……..(2)Solving (1) and (2) T₂ = 372 K
T₁ = 99⁰C = Temperature of source.
Related Questions:
- Eight drops of a liquid of density ρ and each of radius a are falling through air
- The time period of a mass suspended from a spring is T. If the spring is cut into four
- A force of 10N is applied on a body for 3 sec and the corresponding displacement 6 m.
- A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
- An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply