| ⇦ | 
| ⇨ |
An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57×10⁻² T. If the value of e/m is 1.76×10¹¹ C/kg, the frequency of revolution of the electron is
Options
(a) 1 GHz
(b) 100 MHz
(c) 62.8 MHz
(d) 6.28MHz
Correct Answer:
1 GHz
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- Light is emitted when
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- A person wants a real image of his own, 3 times enlarged. Where should he stand
- An unpolarised beam of intensity I₀ falls on a polaroid. The intensity
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- Light is emitted when
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- A person wants a real image of his own, 3 times enlarged. Where should he stand
- An unpolarised beam of intensity I₀ falls on a polaroid. The intensity
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply