| ⇦ |
| ⇨ |
An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, the value of n is
Options
(a) 3
(b) 4
(c) 5
(d) 2
Correct Answer:
4
Explanation:
KEₘₐₓ = 10 eV ? = 2.75 eV
Total incident energy
E = ? + KEₘₐₓ = 12.75 eV
Energy is released when electron jumps from the excited state n to the ground state.
E₄ – E₁ = {-0.85 – (-13.6) eV}
= 12.75 eV value of n = 4.
Related Questions: - The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- A moving neutron collides with a stationary α-particle.The fraction of the kinetic energy
- A photosensitive metallic surface has work function, hν₀. If photons of energy
- Bohr’s postulates quantizes
- A planar coil having 12 turns carries 15 A current. The coil is oriented with respect
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- A moving neutron collides with a stationary α-particle.The fraction of the kinetic energy
- A photosensitive metallic surface has work function, hν₀. If photons of energy
- Bohr’s postulates quantizes
- A planar coil having 12 turns carries 15 A current. The coil is oriented with respect
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply