An electron in the hydrogen atom jumps from excited state n to the ground state

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An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, the value of n is

Options

(a) 3
(b) 4
(c) 5
(d) 2

Correct Answer:

4

Explanation:

KEₘₐₓ = 10 eV ? = 2.75 eV
Total incident energy
E = ? + KEₘₐₓ = 12.75 eV
Energy is released when electron jumps from the excited state n to the ground state.
E₄ – E₁ = {-0.85 – (-13.6) eV}
= 12.75 eV value of n = 4.

Related Questions:

1. The speed of electromagnetic waves in vaccum is equal to
2. When a current of (2.5±0.5) A flows through a wire, it develops a potential difference
3. Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å
4. The circular motion of a particle with constant speed is
5. If the angular momentum of any rotating body increase by 200 % , then the increase

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

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