| ⇦ |
| ⇨ |
An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰ to an electric field of strength 10⁴ NC⁻¹. If it experiences a torque of Nm, the potential energy of the dipole is
Options
(a) 2.45 J
(b) 0.0245 J
(c) 245.0 J
(d) 24.5 J
Correct Answer:
24.5 J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An inductor coil is connected to a 12 V battery and drawing a current 24 A. This coil
- The distance travelled by a particle starting from rest and moving with an acceleration
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
- A motorcycle moving with a velocity 72 kmh⁻¹ on a flat road takes a turn
- The work done in which of the following processes is zero?
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An inductor coil is connected to a 12 V battery and drawing a current 24 A. This coil
- The distance travelled by a particle starting from rest and moving with an acceleration
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
- A motorcycle moving with a velocity 72 kmh⁻¹ on a flat road takes a turn
- The work done in which of the following processes is zero?
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Torque=PE sin¢
10√2= P×10^4 sin 30°
P=2√2×10^-3
U=PE cos 30°
U=2√2×10^-3× 10^4 cos 30°
=24.5 J
Torque=PE sin¢
10√2= P×10^4 sin 30°
P=2√2×10^-3
U=PE cos 30°
U=2√2×10^-3× 10^4 cos 30°
=24.5 J
Torque=PE sin¢
10√2= P×10^4 sin 30°
P=2√2×10^-3
U=PE cos 30°
U=2√2×10^-3× 10^4 cos 30°
=24.5 J