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An alternating voltage e=200s in100t is applied to a series combination of R= 30Ω and an inductor of 400 mH. The power factor of the circuit is
Options
(a) 0.01
(b) 0.05
(c) 0.042
(d) 0.6
Correct Answer:
0.6
Explanation:
Xʟ = Lω = 0.4 × 100 = 40
R = 30 Ω
.·. Power factor, cos ɸ = R / √(R² × Xʟ²) = 30 / √(R² × Xʟ²) = 30 / √(30² × 40²) = 0.6
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
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