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An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
Options
(a) 1 / Ze
(b) v²
(c) 1 / m
(d) 1 / v⁴
Correct Answer:
1 / m
Explanation:
Kinetic energy of alpha nucleus is equal to electrostatic potential energy of the system of the alpha particle and the heavy nucleus. That is,
1/2 mv² = 1/4π?￢ﾂﾀ . qαZe / r₀
where r₀ is the distance of closest approach
r₀ = 2/4π?￢ﾂﾀ . qαZe / mv²
r₀ ∞ Ze ∞ qα ∞ 1/m ∞ 1/v²
Hence option (c) is correct.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
- A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
- The frequency of a light wave in a material is 2 x 10¹⁴ Hz and wavelength is 5000Å.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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