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An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
Options
(a) 1 / Ze
(b) v²
(c) 1 / m
(d) 1 / v⁴
Correct Answer:
1 / m
Explanation:
Kinetic energy of alpha nucleus is equal to electrostatic potential energy of the system of the alpha particle and the heavy nucleus. That is,
1/2 mv² = 1/4π?¬ツタ . qαZe / r₀
where r₀ is the distance of closest approach
r₀ = 2/4π?¬ツタ . qαZe / mv²
r₀ ∞ Ze ∞ qα ∞ 1/m ∞ 1/v²
Hence option (c) is correct.
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Topics: Atoms and Nuclei
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The horizontal range and maximum height attained by a projectile are R and H,respectively
- A galvanometer has a resistance 50Ω. A resistance of 5Ω is connected parallel to it.
- When aluminium is added as an impurity to silicon, the resulting material is
- A block of mass 0.50 kg is moving with a speed of 2.00 ms⁻¹ on a smooth surface.
- A tuning fork gives 4 beats with 50 cm length of a sonometer
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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