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An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
Options
(a) 1 / Ze
(b) v²
(c) 1 / m
(d) 1 / v⁴
Correct Answer:
1 / m
Explanation:
Kinetic energy of alpha nucleus is equal to electrostatic potential energy of the system of the alpha particle and the heavy nucleus. That is,
1/2 mv² = 1/4π?¬ツタ . qαZe / r₀
where r₀ is the distance of closest approach
r₀ = 2/4π?¬ツタ . qαZe / mv²
r₀ ∞ Ze ∞ qα ∞ 1/m ∞ 1/v²
Hence option (c) is correct.
Related Questions: - A body of mass 2 kg travels according to the law x(t)=pt+qt²+rt³
- If the magnetising field on a ferromagnetic material is increased, its permeability
- Which one of the following statements is WRONG in the context of X-rays generated
- α- particles, β – particles and γ – rays are all having same energy.
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 2 kg travels according to the law x(t)=pt+qt²+rt³
- If the magnetising field on a ferromagnetic material is increased, its permeability
- Which one of the following statements is WRONG in the context of X-rays generated
- α- particles, β – particles and γ – rays are all having same energy.
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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