An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze

⇦

⇨

An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to

Options

(a) 1 / Ze
(b) v²
(c) 1 / m
(d) 1 / v⁴

Correct Answer:

1 / m

Explanation:

Kinetic energy of alpha nucleus is equal to electrostatic potential energy of the system of the alpha particle and the heavy nucleus. That is,
1/2 mv² = 1/4π?￢ﾂﾀ . qαZe / r₀
where r₀ is the distance of closest approach
r₀ = 2/4π?￢ﾂﾀ . qαZe / mv²
r₀ ∞ Ze ∞ qα ∞ 1/m ∞ 1/v²
Hence option (c) is correct.

Related Questions:

1. An open pipe resonates with a tuning fork of frequency 500 Hz. It is observed
2. A vibration magnetometer placed in magnetic meridian has a small bar magnet
3. A body is under stress F and has Young’s modulus Y, then the energy
4. An electric lamp is connected to 220 V, 50 Hz supply. Then the peak voltge is
5. Three solids of masses m₁,m₂ and m₃ are connected with weightless string

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends