An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus.

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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of

Options

(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm

Correct Answer:

10⁻¹² cm

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

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Topics: Radioactivity (83)
Subject: Physics (2479)

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