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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- To observed diffraction, the size of the obstacle
- A particle moves a distance x in time t according to equation x = (t + 5)⁻¹
- Depletion layer contains
- IF A⃗ and B⃗ are two vectors and θ is the angle between them
- The energy of a hydrogen atom in the ground state is – 13.6 eV. The energy of a He⁺ ion
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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