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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- A car is moving with uniform acceleration. It covers 200 m in 2 sec and 220 m
- Wb/m² is equal to
- According to Hook’s law of elasticity, if stress is increased, the ratio of stress
- For a normal eye, the cornea of eye provides a converging power 40 D and the least
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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